Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(f2(f2(f2(j, a), b), c), d) -> f2(f2(a, b), f2(f2(a, d), c))
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(f2(f2(f2(j, a), b), c), d) -> f2(f2(a, b), f2(f2(a, d), c))
Q is empty.
Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
F2(f2(f2(f2(j, a), b), c), d) -> F2(a, d)
F2(f2(f2(f2(j, a), b), c), d) -> F2(f2(a, b), f2(f2(a, d), c))
F2(f2(f2(f2(j, a), b), c), d) -> F2(f2(a, d), c)
F2(f2(f2(f2(j, a), b), c), d) -> F2(a, b)
The TRS R consists of the following rules:
f2(f2(f2(f2(j, a), b), c), d) -> f2(f2(a, b), f2(f2(a, d), c))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F2(f2(f2(f2(j, a), b), c), d) -> F2(a, d)
F2(f2(f2(f2(j, a), b), c), d) -> F2(f2(a, b), f2(f2(a, d), c))
F2(f2(f2(f2(j, a), b), c), d) -> F2(f2(a, d), c)
F2(f2(f2(f2(j, a), b), c), d) -> F2(a, b)
The TRS R consists of the following rules:
f2(f2(f2(f2(j, a), b), c), d) -> f2(f2(a, b), f2(f2(a, d), c))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.